Need help - What\'s the SD for playing starting hands?
 

Happy new year all. This is not a very practical question, but I am curious. If I'm playing pretty tight, say around 10% of all starting hands then I should on average play 1 hand per orbit on a ten handed table right? But what is the standard deviation for playing 1 out of 10 hands?

I ask b/c I was sitting at a table last night with a brutal run of crappy cards and was wondering what the SD for such an event was.

A hui hou,
Adam

Re: Need help - What\'s the SD for playing starting hands?
 

Standard deviation for a proportion p is Sqrt(p (1-p)/n), where n is the number of trials (for decent-sized n, like 25ish). So, for p = .1, n = 10, the SD is .09, using the approx. It can be manually found that the SD is really .161, so n=10 isn't quite large enough. More usefully, I guess, for 60 hands, SD is .03878, so you're playing 10% +/- 7.5% of your hands 95% of the time, so being card dead should be actually somewhat commonplace.

Thanks (nm)
 

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