HARDEST QUESTION I CAN THINK OF
I donno the answer to this problem, but I'm hoping some of you could solve it for me.
What is the probability of 1) top pair 2) bottom 2 pair 3) middle 2 pair 4) top 2 pair 3) three of a kind 4) nut straight from the flop, being the winning hand. thanks, |
Re: HARDEST QUESTION I CAN THINK OF
How can you flop middle 2 pair?
~D |
Re: HARDEST QUESTION I CAN THINK OF
Top pair of Aces is going to hold up a lot more than a top pair of 6's
|
Re: HARDEST QUESTION I CAN THINK OF
lol... true, forgot wasn't thinking
|
Re: HARDEST QUESTION I CAN THINK OF
You can replace middle two-pair with top and bottom pair which wasn't on the list.
That being said, I don't think a precise answer can be given and I don't think the answer would be very useful. |
Re: HARDEST QUESTION I CAN THINK OF
you need to tie down the variables a bit more to get some exact answers
for instance, taking only random hands into consideration, if you had top pair with JcTs and a Jd6d2d flop against two opponents you would win 47% of the time with JcTs and a Jd6h2s flop against two opponents you would win 67% of the time |
Re: HARDEST QUESTION I CAN THINK OF
How did you mathematically determine that? I think this question would help me dramatically, when i'm first to bet with top pair and theres x number of players - so that i wouldn't get reraised when a scare card comes.
|
Re: HARDEST QUESTION I CAN THINK OF
only bruce could work that out mathematically - i had to use a poker programme!
|
All times are GMT -4. The time now is 08:05 PM. |
Powered by vBulletin® Version 3.8.11
Copyright ©2000 - 2024, vBulletin Solutions Inc.