Re: Two Questions
 

Just a) for now.


Let P(n)= the probability of throwing a pair of dice n times w/o throwing a seven.


P(n)={5/6}^n


Now P(3)> 1/2 while P(4)

question A is misleading.
 

question a is misleading. it can be interpreted as: 'how many times must you throw 2 dice that the next throw is more likely than not to be a 7?' or as 'how many times must you throw 2 dice so that you will be more likely than not to have thrown a 7 in that sequence?'

Re: question A is misleading.
 

1. Never 2. 20,000 If the chances are 1 out of 40,000 then half the time i will hit it before 20,000 and half the time I will hit it after 20,000.