Probability of AAxx in Omaha
Can anyone tell me the chance of being deal a pair of aces down in omaha. I'm trying to remember my maths from school, and I think it would be something like,
(c(2,48) * c(2,4)) / c(4,52) which is about 2.5%, or 40-1, which feels about right. Can anyone tell me if this is correct. Thanks. |
Re: Probability of AAxx in Omaha
Looks right to me.
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