easy probability question
you have 4 dice. you roll them all. what are the chances that exactly 1 die shows a 3 or a 4 (and no other 3s or 4s are showing)?
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Re: easy probability question
(1/3) * (2/3)^3 * 4 = 32/81
first, consider the first die coming up 3 or 4 and the rest coming up not... then multiply by four to account for other possibilities. |
Re: easy probability question
thanks a lot.
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