Another One Card Game Theory Problem
 

Both players ante the same amount and get a car from zero to one. Player B's card is again face up but this time he cannot draw. Player A can, if he chooses, draw once. After which he can choose to bet the pot.

Obviously if he stands pat, he will always bet. So the questions are.

1. How often should he bet when he draws? (Is it simply those times he wins plus a percentage equal to half of the chance he will outdraw?)

2. How often should he stand pat when he doesn't have B beaten?

3. How large a card would we have to give B to give him an edge. (If there was no draw it would be .67. See why?)

PS. I want this answer for the game I play in as well as for its theoretical interest.

Re: Another One Card Game Theory Problem
 

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3. How large a card would we have to give B to give him an edge. (If there was no draw it would be .67. See why?)

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I'll go with (1+sqrt(2))/3 =~ .805 until someone claims otherwise. Wouldn't be the first arithmetic error I made.

What is the probability that B calls a bet, if A bet without drawing?

alThor