Another quiz..
 

I expect 5/5 GoT [img]/images/graemlins/smile.gif[/img]

1) After you burn down a candle, you get a stub. By using 6 stubs, you can make a new candle. You have 1001 stubs, how many new candles can you make?

2) The sum of Eve and Ann's ages is 44. Eve is twice as old as Ann was when Eve was half as old as Ann will be when Ann is three times as old as Eve was when Eve was three times as old as Ann. How old is Eve?

3) Write a 10-digit number. The first digit tells how many zeroes there are in the number. The second digit tells how many ones that are in the number. The third digit tells how many twos there are in the number, and so on. The last number tells how many nines there are in the number. What is this number?

4) AB * C = DE * F = GHI. The letters represent all the numbers 1-9. What is the number GHI? There are two solutions.

5)A man left home one day and made three left turns and met a man with a mask on. Who did he meet?

aloiz

Re: Another quiz..
 

<font color="white"> 1. 200 </font>

Re: Another quiz..
 

<font color="white">5. the umpire </font>

Re: Another quiz..
 

Both are correct.

aloiz

Re: Another quiz..
 

I have no desire to try to figure out #2...just too confusing.

Re: Another quiz..
 

1 <font color="white"> eventually 200 </font>
3 <font color="white"> 6210001000 </font>
5 <font color="white"> the catcher</font>

Still working on 2 and 4

Re: Another quiz..
 

Opps yea I guess there are two correct answers for #5. Kinda a dumb one I guess.

aloiz

Are you sure about #2?
 

<font color="white">The possibilities I come up with are:

Eve 10, Ann 6
E 20, A 12
E 30, A 18
E 40, A 24

Here's my reasoning:

At one point, Eve was 3x Ann. Start with A1 and E3. Then we look when Ann is 3x Eve. So A9. Now we need Eve's age to be 1/2 Ann's, but we can't because we can't take 1/2 of 9. This rules out starting with any odd number for Ann's original age.

Now we look at Ann=2, Eve =6. Ann's next age is 18 (3x Eve). Eve's next age is 9 (1/2 Ann). When Eve is 9, Ann is 5 (difference in age is 4). Now Eve is 2x Ann's calculated age - 10. And Ann is then 6. This equals 16.

Try for Ann=4, Eve=12. This gives us ages of 20 and 12, equaling 32.

Try for Ann=6, Eve=18. This gives us ages of 30 and 18, equaling 48.

And so on.

I must be missing something</font>

Re: Are you sure about #2?
 

This one is probably the most difficult, and is almost unfair. If no one gets it I'll post a solution in a bit.

aloiz

Still missing something
 

[ QUOTE ]
2) The sum of Eve and Ann's ages is 44. Eve is twice as old as Ann was when Eve was half as old as Ann will be when Ann is three times as old as Eve was when Eve was three times as old as Ann. How old is Eve?

[/ QUOTE ]

"...when Eve was 3x as old as Ann." Does this mean 3x as old as Ann was at that time? Or 3x as old as Ann is now?

Re: Still missing something
 

Everything retains the context of the previous thing said. So yes 3x as old as Ann was at the time.

As I read this over, I still get frustrated trying to parse the grammer. I've always hated problems like these.

aloiz

Re: Are you sure about #2?
 

I re-read this more closely, and since you mentioned it in all fairness I should tell you can take 1/2 of 9. In other words, the answer is a fraction.

aloiz

ok, I\'ll have it in a sec then
 

[ QUOTE ]
I re-read this more closely, and since you mentioned it in all fairness I should tell you can take 1/2 of 9. In other words, the answer is a fraction.

aloiz

[/ QUOTE ]

Re: ok, I\'ll have it in a sec then
 

<font color="white"> Eve 27.5 Ann 16.5 </font>

Re: ok, I\'ll have it in a sec then
 

Very nice.

aloiz

Re: Another quiz..
 

<font color="white">1: 200 new candles / no explaination needed.
2: 27.5 years old / E=2[4.5(E-A)/2-(E-A)] where E+A=44
3: 6,210,001,000 / just had to think about it for a while
4: 156 / Use a series of matrices and eliminate the ones that have no solution without repeating digits.
5: The home-plate Umpire or the Catcher / Baseball, obviously</font>

GoT

Re: Another quiz..
 

First three are right (nice solution for #2). For #5 I don't know what you mean, but that's not it.

aloiz

Re: Another quiz..
 

For Question #4, here's the system I tried using. It comes up with no solution possible, though, so there's gotta be a flaw somewhere. Maybe somebody else can help me find it...

System: AB * C = DE * F = GHI
<font color="white">First, some logic. Let's eliminate what I CANNOT be. It cannot be 1, since there are no two pairs of numbers that both multiply to a number that ends in 1. 7x3 does, but that leaves the only two other odd numbers as 5 and 9, which obviously doesn't work. "I" can't be 3, 5, or 9 for the same reasons (somebody correct me if I'm wrong here and am missing something that'd work). So that leaves the 2,4,6, and 8.

If I is 2:

That would mean {B and C} and {E and F} are {8 and 4} and {7 and 6}, NOT respecitively. Oh, WAIT! 4 and 3 and 7 and 6 are also possible. Same thing goes with other possibilities for I that I overlooked. I'll have the answer in less than 5 minutes. [img]/images/graemlins/smile.gif[/img]</font>

GoT

Re: Another quiz..
 

damn, I thought for sure it was El Diablo

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My answer for Q4 is:

<font color="white">156. It had the be one of THEE VERY LAST matrices that I tried. Of course.. </font>

GoT

Re: Another quiz..
 

First three are right (nice solution for #2). For #5 I don't know what you mean, but that's not it.

What do you mean? I'm almost positive my answer for Q5 is correct.

GoT

Re: Another quiz..
 

Opps...sorry I only highlighted part of the answer and all I saw was "The home".

aloiz

Re: Another quiz..
 

Nice. The other answer is:
<font color="white">
174
</font>

aloiz

Re: Are you sure about #2?
 

in all fairness I should tell you can take 1/2 of 9. In other words, the answer is a fraction.

You really didn't have to give this away. It's just a simple algebraic equation. They should be able to come to the solution themselves without knowing whether or not it's fractional. By giving people this hint, you're just encouraging them to try to solve the problem using the trial and error method, which is never the best way to solve a problem and won't help people become better at ML at all.

GoT