Re: Party Poker Sidebets
[ QUOTE ]
EV = $8 *(1/8.5) - 1 *(7.5/8.5) = .94 - .88 = -6.25% [/ QUOTE ] EV = $7 *(1/8.5) - 1 *(7.5/8.5) = -5.88% The payout is 8 FOR 1, which means 7 TO 1, not 8 TO 1. Otherwise it would be +EV. |
Re: Party Poker Sidebets
Thanks all, this "8 for 1" explanation makes everything clear.
That is very sneaky of them. |
Re: Party Poker Sidebets
I stoopid.
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8 for 1 v. 8 to 1
Bruce,
In addition to craps, this sneakiness happens in video blackjack. "All winning hands pay 2 for 1". "Blackjack is an automatic winner and pays 2 for 1". |
Re: 8 for 1 v. 8 to 1
I haven't played this game, so I know very little about it, but I thought of this. I assume it is a push if there is no flop.
In that case if you have a significant chance of influencing whether there will be a flop or not, you could have an edge. For example: you bet $10k on all red in the .50-1 game, and you are dealt two red aces in the big blind. Someone raises, and it is folded around to you. You fold. If you were dealt 9 [img]/images/graemlins/club.gif[/img] 4 [img]/images/graemlins/spade.gif[/img], you would call. Right? |
Re: 8 for 1 v. 8 to 1
I like you're thinking, but unfortunately the maximum sidebet is 1BB on the 10$ SNGs. You could never gain enough leverage to make up for giving up the ev of pushing to prevent flops.
If you could selectively place bets after you've seen your 2 cards, I get a +ev of about 6.1% |
Re: 8 for 1 v. 8 to 1
It seems like you could collude to rip this game off real easily.
If you got a team of 10 players, all bet red. If the count of red cards is < x, see the flop. If not, someone raise and everyone else fold. |
Re: 8 for 1 v. 8 to 1
Getting ten people at a table to cooperate with each other doesn't sound real easy to me.
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Re: 8 for 1 v. 8 to 1
Sounds like a plan.
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Re: 8 for 1 v. 8 to 1
Find 10 friends, enter a tournament. I think you can even bet if you are watching too. Get 20 more friends to watch.
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