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-   -   Ultimate spreading Royal Holdem, but only limit (http://archives2.twoplustwo.com/showthread.php?t=371431)

GrannyMae 11-04-2005 09:29 AM

Re: Ultimate spreading Royal Holdem, but only limit
 
[ QUOTE ]
Just giving this game a try..got quite an interesting situation i thought i would share:

If you have AA and flop top set, then you can only be beaten by quads or a str8 flush.

E.g.

You: AA
Opponent: KQ

Flop: A T J

Even though your opponent has you beaten, you can still only lose to quads or a str8 flush. This is because (barring quads or str8-flushs) one of 2 things will happen:

1, The board will pair, and you now have a full house beating villian's straight.

2, The board will make the nut str8 and you will split the pot.

This just shows how strong AA is in this game..

Conversely, i think hands like TT and JJ are poor as you are pretty much always going to be drawing to 2 outs.

[/ QUOTE ]


great post. any other nuggets like this? or is it only AA flopped set that results in a situation /rule like this?

Boolean 11-04-2005 09:43 AM

Re: Ultimate spreading Royal Holdem, but only limit
 
Sigh, I guess I'm going to spoil the beans on how to really play this game. Pretty much, my starting hands consist of AA, KK, AK, KQ, and QQ. That's it. Suitedness has no effect as royals are so rare. It's of course a 20-card deck so your outs are like so:

After the flop:
1/15 = 1:14
2/15 = 1:7
3/15 = 1:4
4/15 = 1:2.75
5/15 = 1:2

After the turn:
1/14 = 1:13
2/14 = 6:1
3/14 = 3.7:1
4/14 = 2:5:1

Flopping a straight is an automuck in a full-table game. You are at best tied by the river. Bottom set is also pretty dangerous. Case in point:

You have JJ
flop shows KQJ
You lose to KQ and QQ (albeit unlikely) if a Q or a K comes, and even if you aren't behind them, an AK or KQ can also pick up an Ace or King on the river. Your best shot here is to have runner-runner Tens. The only hands that would beat you then are the other pocket pairs KK and QQ.

Middle set can be quite profitable if you know how to play it however. Case in point:

You have QQ, the flop shows KQT
If the board pairs the ten, you likely have the best hand unless you're up against KK. It's a very good way of getting a decent pot, and I play QQ for just this reason. If the K pairs however, you're losing to KT, KQ, and KJ and AK if they improve on the river.

Top set and top two pair is what you should shoot for. With top two pair you have 4 outs twice (provided there are no royal draws and you don't run into quads), or (4/15)+(4/14)=55% which means you're a favorite from the flop. Bet/raise/cap. Top set, likewise. Unless you run into quads or the board shows a straight, you will win.

Anywho, I know this is formatted pretty ugly, but I hope ya'll enjoy anyhow.

-Boolean

Obliky 11-04-2005 09:50 AM

Re: Ultimate spreading Royal Holdem, but only limit
 
[ QUOTE ]
any other nuggets like this? or is it only AA flopped set that results in a situation /rule like this?

[/ QUOTE ]

Thinking this through a bit more, when you have a set you can not lose to a straight (for the reasons stated in my previous post) as the board will always pair or make the nut straight (which is the only straight you can make in this game btw). The great advantage to having AAA is that you cannot lose to a higher full house, which is obviously your greatest concern if you flop a lower set.

I guess that when you flop a set you actually have either a straight or a full house... as its impossible to get to a showdown and just have a set.

The same also applies to trips..you will always make a str8 or full house by the river.

Also, the odds of flopping a set are 2.5:1, and the odds of making a set by the river are 1.2:1

timprov 11-04-2005 10:22 AM

Re: Ultimate spreading Royal Holdem, but only limit
 
Judging from the table chat, players are stumbling into the game not realizing the premise. I suspect we're in for a spate of "UB is rigged" posts.

Lori 11-04-2005 10:24 AM

Re: Ultimate spreading Royal Holdem, but only limit
 
I just got reported for cheating because apparently I knew what was coming [img]/images/graemlins/shocked.gif[/img]

Lori

timprov 11-04-2005 10:35 AM

Re: Ultimate spreading Royal Holdem, but only limit
 
[ QUOTE ]
I just got reported for cheating because apparently I knew what was coming [img]/images/graemlins/shocked.gif[/img]

Lori

[/ QUOTE ]

By somebody with a straight?

theblitz 11-04-2005 12:18 PM

Re: Ultimate spreading Royal Holdem, but only limit
 
More interesting points:

If the board does not pair then the best you are doing is splitting unless you have the flush. This is for the simple reason that the best hand is on the table.

If it is not a 3 or 4 flush board then it is a split.

The question is: how many of the players will realise that?

---------------------------------------------------

2 pair is a dead hand. It cannot win ever.
This is why:

1. If the board didn't pair then you are at best splitting
2. If the board did pair (not on your cards) then at least 1 of the other players (assuming all 6 are in) MUST have either a str or a FH. This is because only 3 cards don't play so one of the players MUST have the card that completes the str.

-------------------------------------------------------

Trips are a dead hand unless you fill up. Same reason as above.

-------------------------------------------------------

I'm sure there are more and I will add them if I think of them.

This can be an amazing game to catch some fish.

timprov 11-04-2005 12:19 PM

Re: Ultimate spreading Royal Holdem, but only limit
 
[ QUOTE ]

2 pair is a dead hand. It cannot win ever.


[/ QUOTE ]

I've seen several showdowns where two pair beat a worse two pair, or players split playing the 2 pair on the board. It happens more often shorthanded.

theblitz 11-04-2005 12:26 PM

Re: Ultimate spreading Royal Holdem, but only limit
 
Yep.
But if all 6 players are in to the showdown then this can NEVER happen.

theblitz 11-04-2005 12:32 PM

Chance of the board pairing
 
He we go.

Very simple calculation:

Calculate the chance of board NOT pairing:
First card is irrelevant. Say A.
Second card must not be an A so can only be 16 out of the 19 left.
Third card is 12/18.
Fourth card is 8/17.
Fifth is 4/16.

Give 16/19 * 12/18 *8/17 * 4/16 = 0.066

So chance of pairing = 1-0.066 = 0.954 or 95.4%.

Next I need to calculate what the chances are of winning if you have a PP.


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