Re: None of this nursery school stuff - a proper maths problem. 25$ re
 

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x^2+68-y^5
x=+/- (y^5-68)^1/2
y has to be >= 68^1/5
x can be any real number

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No, x can not be. I assure you that the OP meant, as he clarified later, for x and y to be natural numbers. Otherwise the problem is incredibly uninteresting and not related to any entire body of mathematics called Diophantine equations which is clearly what he intended.

Re: None of this nursery school stuff - a proper maths problem. 25$ re
 

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the problem is too difficult for me.

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FYP

Re: None of this nursery school stuff - a proper maths problem. 25$ re
 

I'm assuming X and Y are integers?

Edit: nm, clicked reply when there were no replies

Re: None of this nursery school stuff - a proper maths problem. 25$ reward
 

[censored], if I had my TI-92 or whatever its called, I could figure this out.

Re: None of this nursery school stuff - a proper maths problem. 25$ reward
 

yeah, i just googled Diophantine equations. this is way over my head. u guys have fun.

Re: None of this nursery school stuff - a proper maths problem. 25$ reward
 

Why do I think this is one of those "unanswered" problems that gets a million bucks if the correct answer is published.

Re: None of this nursery school stuff - a proper maths problem. 25$ reward
 

We need matt damon

Re: None of this nursery school stuff - a proper maths problem. 25$ re
 

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We need matt damon

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I expect his gimmick account any moment.

Re: None of this nursery school stuff - a proper maths problem. 25$ re
 

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Why do I think this is one of those "unanswered" problems that gets a million bucks if the correct answer is published.

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it's not. it's just some random diophantine equation.

citanul

Re: None of this nursery school stuff - a proper maths problem. 25$ reward
 

I am a born mathematical genius (solved high school problems at age of 7) but haven't kept up with it lately. My intuition though tells me there are no solutions without quite finding the proof in my head.

So I will offer my 2 cents to lay the foundation for somebody else. When you ^2 a number you basically just double up the number of factors it consist of (i.e. 30=2*3*5 while 900=2*2*3*3*5*5). When you add 68 you add 2*2*17. The number you get after adding 68 has to contain a number of each factor dividable by 5. I think the assymetric nature of 68 containing of 1 factor of 1 kind and 2 of the other messes that up.

No proof, so I don't claim the $25.

EDIT: Just for clarification I know that addition does not mean that you add the factors (that is multiplying), so somebody need to look into the effect of adding the assymetric number of 68.