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djk123
10-11-2005, 05:47 PM
Could anyone explain to me how you would calculate the odds of in a 3 handed game with hands: KK, QQ, 44, the flop coming KQ4?

BruceZ
10-11-2005, 06:06 PM
[ QUOTE ]
Could anyone explain to me how you would calculate the odds of in a 3 handed game with hands: KK, QQ, 44, the flop coming KQ4?

[/ QUOTE ]

46 cards remaining, and 2 of each rank K, Q, 4, so probability of flopping those 3 ranks are:

2/46 * 2/45 * 2/44 * 6 = 1896.5-to-1.

We multiply by 6 since the 3 cards can come in any of 6 orders.

Or, 6/46 * 4/45 * 2/44 = 1896.5-to-1.

That is, 6 ways to choose the first card, 4 ways to pick the second, and 2 ways to pick the third.

Also, 8/C(46,3) = 1896.5-to-1.

ninjaunderwear
10-11-2005, 06:07 PM
Odds of flopping KQ4 when a pair of each has been dealt is 48/91,080 = 0.0527% or about 1,897 to 1.

The first card on the flop can come any of the 6 set cards, second card can come any of the 4 remaining set cards, and the third flop card must come from the 2 remaining cards to form the final set. 6 * 4 * 2 = 48