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08-28-2005, 12:35 PM
What is the probability that an opponent have one or two clubs when the board has four clubs, and how do I calculate it?
In Hold'em

Martin Carlsson
Aalborg, Denmark

08-28-2005, 03:21 PM
Hi Martin

I assume that there are 4 cards on the board, and you do not have a club. There are 46 unseen cards, and 9 clubs left. You now have to calculate the probability that he does NOT have a club. Of 46 cards 37 are not clubs.
(37/46)*(36/45) = 64%. So in 36% of they time he will have one or more clubs.

Jesper Jørgensen, Denmark

08-29-2005, 06:30 AM
Ok,tnx

Can you recommend a book that explains standard probability?
I don't need anything fancy (jet), just an introduction.

It is ok, if it is danish.

Martin Carlsson
Aalborg, Denmark

paulish
08-29-2005, 10:57 PM
Get Chance: A Guide to Gambling, Love, The Stock Market &amp; Just About Everything Else (http://www.amazon.com/gp/product/customer-reviews/1568583168/ref=cm_cr_dp_pt/002-0037956-2294422?%5Fencoding=UTF8&amp;n=283155&amp;s=books)
by Amir D. Aczel. High Stakes, 2005.

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11-21-2005, 05:10 AM
I just finished reading it. Great book!
I can recommend it to anyone, who want an introduction to probability.

DoomSlice
11-21-2005, 11:21 AM
Questions like this are best left to the realm of theory, since the way an opponent plays a hand should tip you off more as to whether he has a club (conditional probability!).