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View Full Version : Probability of 3 pocket Pairs being dealt in 3 handed game?

balt999
02-19-2003, 05:36 PM
I was watching the 2002 WSOP on ESPN2 last night and saw an amazing hand....It was 3 handed: Julian Gardner (on the button) was dealt pocket 10's.....Ralph Perry (SB) was dealt two Jacks, and Robert Varkoni (BB, and Mr. Lucky) was dealt Pocket Rockets...turned out to be a pivotal hand cause it knocked Ralph Perry out and gave Varkoni a huge chip lead...

My question is what are the probability of 3 pocket pairs being dealt in a 3 handed-game? Just seems so unreal...

Thanks

BruceZ
02-20-2003, 09:45 AM
The probability of 3 different pocket pairs in a 3 handed game are:

[13*6/(52*51/2)]*[12*6/(50*49/2)]*[11*6/(48*47/2)] = 1 in 4943.

marbles
02-20-2003, 01:14 PM
Wow, that's kinda nuts. Even crazier is that all three pairs were 10's or better. Did Julian's tens see the flop?

SKatuska
02-20-2003, 01:51 PM
No, Ralph went all in, Robert went all in, and Julian folded his tens (later proven to be the right choice).

SKatuska
02-20-2003, 01:52 PM
I meant to say Robert called Ralph, he had a substantial chip lead and had no need to go all in.