View Full Version : HARDEST QUESTION I CAN THINK OF
bob2007
12-14-2002, 12:19 PM
I donno the answer to this problem, but I'm hoping some of you could solve it for me.
What is the probability of
1) top pair
2) bottom 2 pair
3) middle 2 pair
4) top 2 pair
3) three of a kind
4) nut straight
from the flop, being the winning hand.
thanks,
How can you flop middle 2 pair?
~D
DenverGuy39
12-20-2002, 12:40 AM
Top pair of Aces is going to hold up a lot more than a top pair of 6's
bob2007
12-20-2002, 04:23 PM
lol... true, forgot wasn't thinking
Dynasty
12-20-2002, 09:17 PM
You can replace middle two-pair with top and bottom pair which wasn't on the list.
That being said, I don't think a precise answer can be given and I don't think the answer would be very useful.
Mike Haven
12-21-2002, 12:14 PM
you need to tie down the variables a bit more to get some exact answers
for instance, taking only random hands into consideration, if you had top pair with JcTs and a Jd6d2d flop against two opponents you would win 47% of the time
with JcTs and a Jd6h2s flop against two opponents you would win 67% of the time
bob2007
12-21-2002, 07:39 PM
How did you mathematically determine that? I think this question would help me dramatically, when i'm first to bet with top pair and theres x number of players - so that i wouldn't get reraised when a scare card comes.
Mike Haven
12-21-2002, 09:26 PM
only bruce could work that out mathematically - i had to use a poker programme!
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