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SGS
04-14-2005, 10:50 PM
Ok so how in 3 card poker would you calculate the probability of recieving 3 of a kind? I figured it would be (C(4,3)*13)/C(52,3). This gives me a really small number though and unsure if it is correct.

And I am really unsure of how to compute the probability of getting a straight. I was thinking (12*4^3-48)/C(52,3). Does this seem right or not? Thanks in advance.

SGS

gaming_mouse
04-14-2005, 11:09 PM
[ QUOTE ]
Ok so how in 3 card poker would you calculate the probability of recieving 3 of a kind? I figured it would be (C(4,3)*13)/C(52,3). This gives me a really small number though and unsure if it is correct.

And I am really unsure of how to compute the probability of getting a straight. I was thinking (12*4^3-48)/C(52,3). Does this seem right or not? Thanks in advance.

SGS

[/ QUOTE ]

3 of kind looks right.

Straight looks right except for the " - 48" part. Where are you getting that?

SGS
04-14-2005, 11:44 PM
Don't you have to subtract the straight flushes? 48 possibilities?

SGS

BruceZ
04-15-2005, 12:32 AM