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12-19-2004, 09:20 AM
Well, maybe not so simple, since I'm not sure how to figure it out on my own. This question is being spawned from an unfortunate multi-table tourney I participated in.

A certain player is dealt kings four times, twice at a six-handed table and twice at a full (ten-handed) table. What are the odds that aces will be out every time?

MortalWombatDotCom
12-19-2004, 06:16 PM
there was just a thread that would answer this. i don't feel like searching for it. i did the calculation "the hard way", and someone (almost undoubtedly gm) pointed out an easier way which is almost certainly inclusion/exclusion.

i think we all agreed that just using the chance of each player getting aces was close enough to correct to not worry about it since the chance of two people getting aces is so rediculously remote.

since two Ks are out, the chance of getting dealt two aces is 4/50 * 3/49 = .00489795918367346938

call that value a.

the chance of someone getting dealt AA against our hero all four times is approximately a^4 * 5 * 5 * 9 * 9 = .00000116542860715575

pretty unlikely.

12-21-2004, 01:23 AM
I'm not sure if that makes me feel better or worse . . .

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elitegimp
12-21-2004, 05:46 PM
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I'm not sure if that makes me feel better or worse . . .

/images/graemlins/crazy.gif

[/ QUOTE ]

did you at least hit your set one of those 4 times?