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SGS
12-06-2004, 07:18 PM
Here is a problem on my freinds final and he asked me for help but I apparently forgot exactly how to do it. This is pretty simple and straight forward.

Assume the following information:

A tub contains 500 plain m&mís. 13% of them are brown, 14% are yellow, 13% are red, 24% are blue, 20% are orange and 16% are green. Suppose that two m&mís are selected at random from the tub. Assume that the first m&m is replaced before the second is drawn.

Calculate the probability that at least one of the m&mís is blue. Thanks in advance.

SGS

gaming_mouse
12-06-2004, 07:28 PM
76% are non-blue. Just do:

1 - (.76)^2