Hello! How's my Thinking On This One?--Hmmm...

SittingBull · #1 05-12-2003, 05:24 PM

On the river in a Hold'em game,there are 4 of one suit showing and I have one of the suit. Then the Probability that my heads-up opponent has at least one of the same suit is***
1-(C(37,2)/C(45,2)) [img]/forums/images/icons/shocked.gif[/img]
Any fallacy in this thinking?
Just wondering,
SittingBull

1800GAMBLER · #2 05-13-2003, 04:15 AM

By conditional:

3 ways:

SO
OS
SS

S = suited O = Doesn't have the one.

SO/OS = 2*(8/45)*(37/44) + (8/45)*(7/44) =

18/55; 32.7%; just over 1:3.

SittingBull · #3 05-14-2003, 04:16 AM

1-(C(37,2)/C(45,2))=1-0.673=32.7% same as yours..
Hmmm
HappyPokering, [img]/forums/images/icons/laugh.gif[/img]
SittingBull