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  #1  
Old 09-23-2005, 03:56 AM
radek2166 radek2166 is offline
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Default Pocket aces. By autoshuffler.

I was playing in Blackhawk last night. I saw 14 pocket aces in 2 hours. What are the odds of that?

Do you think the shuffler was broke?
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  #2  
Old 09-23-2005, 06:10 AM
testaaja testaaja is offline
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Default Re: Pocket aces. By autoshuffler.

Lets say you played 50 hands/h so it makes 100 hands total. You will get aces 1/51+1/50. So it is only <40% that you even get aces on that 100 hand run. (1/51+1/50)^14 wich comes down to 2.33849641 × 10^(-20) wich is 4.27625203 × 10^19. Well my calculation shows only when you get aces 14 times in a row. If someone could tell me how to calculate those 86 other hands in too I would appreciate thanks.
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  #3  
Old 09-23-2005, 09:24 AM
OrangeKing OrangeKing is offline
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Default Re: Pocket aces. By autoshuffler.

[ QUOTE ]
Lets say you played 50 hands/h so it makes 100 hands total. You will get aces 1/51+1/50. So it is only <40% that you even get aces on that 100 hand run. (1/51+1/50)^14 wich comes down to 2.33849641 × 10^(-20) wich is 4.27625203 × 10^19. Well my calculation shows only when you get aces 14 times in a row. If someone could tell me how to calculate those 86 other hands in too I would appreciate thanks.

[/ QUOTE ]

Also, if the OP meant "saw" as in "any player had them", it makes the event a lot less unusual - he'd expect to see them about 5 times in 100 hands anyway. 14 is still a lot, but I don't think the autoshuffler is broken, unless it can pick the aces out and stack the deck. [img]/images/graemlins/smile.gif[/img]
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  #4  
Old 09-23-2005, 10:23 AM
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Default Re: Pocket aces. By autoshuffler.

And maybe 14 was the number of Aces he saw. So thats only 7 times! [img]/images/graemlins/tongue.gif[/img]
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  #5  
Old 09-23-2005, 11:32 AM
testaaja testaaja is offline
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Default Re: Pocket aces. By autoshuffler.

[ QUOTE ]
[ QUOTE ]
Lets say you played 50 hands/h so it makes 100 hands total. You will get aces 1/51+1/50. So it is only <40% that you even get aces on that 100 hand run. (1/51+1/50)^14 wich comes down to 2.33849641 × 10^(-20) wich is 4.27625203 × 10^19. Well my calculation shows only when you get aces 14 times in a row. If someone could tell me how to calculate those 86 other hands in too I would appreciate thanks.

[/ QUOTE ]

Also, if the OP meant "saw" as in "any player had them", it makes the event a lot less unusual - he'd expect to see them about 5 times in 100 hands anyway. 14 is still a lot, but I don't think the autoshuffler is broken, unless it can pick the aces out and stack the deck. [img]/images/graemlins/smile.gif[/img]

[/ QUOTE ]
Heh I automatically suspected it was that he got them [img]/images/graemlins/blush.gif[/img] well then.
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  #6  
Old 09-23-2005, 01:23 PM
radek2166 radek2166 is offline
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Default Re: Pocket aces. By autoshuffler.

It was 14 PP in a 10 handed game. one guy had them 5 times in an hourand a half.
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  #7  
Old 09-24-2005, 03:38 PM
JustToast JustToast is offline
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Default Re: Pocket aces. By autoshuffler.

[ QUOTE ]
It was 14 PP in a 10 handed game. one guy had them 5 times in an hourand a half.

[/ QUOTE ]

Check his sleeves.
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