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  #1  
Old 04-25-2005, 07:07 AM
M50Paul M50Paul is offline
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Default Looking for a formula

How do you calculate teh following:
1. How many AK combinations are there when 5 cards are seen none of which are AK.

2. How many AA combinations are there with no cards seen

Thanks
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  #2  
Old 04-25-2005, 09:43 AM
PaultheS PaultheS is offline
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Default Re: Looking for a formula

for AK: 4 * 4 = 16 combinations. (ie. Ah can go with any of the four kings, Ac can go with any of the four kings, etc.)

for AA: 4C2 = 4! / 2!2! = 6 combinations.
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Old 04-25-2005, 03:40 PM
M50Paul M50Paul is offline
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Default Re: Looking for a formula

thanks
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Old 04-27-2005, 04:11 PM
LetYouDown LetYouDown is offline
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Default Re: Looking for a formula

[ QUOTE ]

1. How many AK combinations are there when 5 cards are seen none of which are AK.

[/ QUOTE ]
This doesn't change the number of combinations. Are you looking for the odds of having the hand?
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Old 04-27-2005, 10:33 PM
M50Paul M50Paul is offline
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Default Re: Looking for a formula

good point, agree. I was making some tables on odds and other measures and I kind of ran two things together. This particular question was getting at an objective way to detemine how to randomly raise 75% of the time. So in the case of AK -- 16 combinations I would raise any time there was no king of clubs in my hand.
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  #6  
Old 04-27-2005, 10:44 PM
LetYouDown LetYouDown is offline
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Default Re: Looking for a formula

Not to nitpick, but that's not random...that's derived [img]/images/graemlins/grin.gif[/img]
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  #7  
Old 04-29-2005, 09:08 AM
M50Paul M50Paul is offline
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Default Re: Looking for a formula

Well...... it's a non-random, random secletion of an integral part of my digit which gives the the non bias opportunity to rasie with impunity.

So........
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