#1
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Full House By the River
Holdem:
As Ac in the pocket. Can someone provide the explanation/formula for determining the probability of a full house by the river? How about As 9c in the pocket? Much appreciated! |
#2
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Re: Full House By the River
Ignoring cases that produce 4 of a kind, mutually exclusive boards which make a full house with your pocket AA:
1) Trips + Two Pair 2) Trips Alone without A 3) Trips Alone + A 4) Two pair + A 5) One Pair + A Trips + Two Pair (1584 total) Consider a specific full house, say TTT33. How many are there? 4*6 = 24 Now, how many specific full houses are there, excluding any that use aces? nCr(12,2) = 66 So there are 66*24 = 1584 possible boards containing a non-A full house. Trips Alone without A (84480 total) For each card rank, there are 4 ways to make trips. Since we ignore aces, there are 12 card ranks, giving us 48 ways to make trips. Now lets consider how many ways the other 2 cards can come when there are trips on board, and we are not allowed to have aces or pairs. For the first card, there are: 52 - 4 - 4 = 44 possible cards. There are only 40 for the second card. So the total for this section is: 48*44*40 = 84480 Trips Alone + A (4224 total) 2 aces left. 44 cards which are neither aces nor part of the trips. 48*44*2 = 4224 Two pair + A (4752 total) There are 6*6 = 36 ways to make up any specific two pair. There are 66 possible two pair combinations in which neither pair is a pair of aces (see full house calculation above). Since there are two aces left, we have: 36*66*2=4752 One Pair + A (253440 total) The A is fixed, the pair is fixed, and there are 44*40 ways to put together the remaining two cards. There are 12 possible non-ace pairs, 6 ways to make up each one. We have: 12*6*44*40*2 = 253440 Putting It Together We add everything up and divide by the number of possible boards. 1584 + 84480 + 4224 + 4752 + 253440 = 348480 There are nCr(50,5) = 2118760 boards 348480/2118760=.1644, about 16% I think that's right but it's late and I may have forgotten something or made an arithmetic error. You'll have to solve the A9 case on your own [img]/images/graemlins/laugh.gif[/img] BTW, knowing these kinds of odds have little practical value at the poker table. Cheers, gm |
#3
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Re: Full House By the River
So there are 66*24 = 1584 possible boards containing a non-A full house.
If he holds AA then he can't make a non-A full house. [img]/images/graemlins/smile.gif[/img] Lost Wages |
#4
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Re: Full House By the River
[ QUOTE ]
If he holds AA then he can't make a non-A full house. [img]/images/graemlins/smile.gif[/img] [/ QUOTE ] Well, yes, I guess his aces would play. But the point is there is a full house on the board in these cases. gm |
#5
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Re: Full House By the River
Good grief!
Nice job!!!...thanks much! |
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