What's The Chances of This One? 911 NY Drawing

[Peter]

Hey Igor,

indeed, if you roll a die six times and you bet that on the third roll the outcome will be three the probability of this is 1/6. Look at it this way: the first roll may be anything, just as the second, fourth, fifth and sixth. But the third roll must be a three. The probability for this is: 1*1*1/6*1*1*1=1/6.

So chances for the lottery to get 911 as outcome on any given day is 1/1000 (or in correct notation 1*1*1*...*1*1/1000*1*...*1=1/1000 with the 1's and dots representing the string of 1's corresponding to the dates that don't matter and the 1/1000 corresponding to the date you chose.)

Peter

[cardshark]

Yes, Peter. I also gave the math some thought after I made my post. In fact member Mike Haven started another thread <FONT color=”red”>General Gambling>>Probability>>An interesting phenomenon</FONT> and continued on the subject, so I made my reply there.

Still, skeptic as I am, I still think it smells of a fix because of some other elements involved (that can’t be put into numbers). But that’s another discussion.