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Odds on a 3 Flush
I know this is pretty rudimentary, but is the formula for figuring out the odds of making one's three flush to multiply (10/37) by (9/36)=90/1332, giving you odds of 14.8-1? In other words, the odds of hitting one of your suit on the turn multiplied by the odds of then hitting one on the river? This seems the obvious solution to my largely unmathematical mind, but I thought I'd ask if this was right and, if not, what is? Thanks.
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