Decent estimate for my AQo being dominated....

[slimpikkens]

My virgin run in the probability forum.

Is this an acceptable estimate for my AQo being dominated in a 10-handed holdem game?

With 50 cards still out, there are 1225 two-card combinations available. (50*49/2*1) = 1225

AA 3 combinations
KK 6
QQ 3
AK 12

for a total of 24 combinations that dominate me....

24/1225 = .01959

multiplied by 9 = .1763 = 17.63%

Close enough? I've read a couple posts today that mention multiplying by 9 doesn't account for the chance of more than one dominating hand....is there a way to estimate how much I could be off? Or is it negligible?

Thanks for any input....