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#11
08-02-2005, 03:11 PM
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Re: starting hands how many please respond
i think ill do it on a calculater while playing online till i do it naturally
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#12
08-02-2005, 11:21 PM
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Re: starting hands how many please respond
[ QUOTE ]
i think ill do it on a calculater while playing online till i do it naturally [/ QUOTE ] Your calculation assumes that your opponent will play any two cards dealt to him with equal regularity. I guess that true with some people though. Sidenote to this. There are 169 different hand "types". AA, AKo, AKs, etc. Not that I can calculate it, but that's what pokertracker shows.
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#13
08-02-2005, 11:27 PM
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Re: starting hands how many please respond
[ QUOTE ]
Yes, but that counts A[img]/images/graemlins/spade.gif[/img] J[img]/images/graemlins/diamond.gif[/img] as a different hand from J[img]/images/graemlins/diamond.gif[/img] A[img]/images/graemlins/spade.gif[/img]. For example, suppose you want to figure out the probability of getting AJ offsuit. You could say there are four different Aces, and three offsuit Jacks per Ace, for 12 different hands. That's 12/2,652. Or you could divide both numbers by two, to get 6/1,326. You get the same probability either way. You just have to be consistent. [/ QUOTE ] I'm too tired to figure out where the error in this is, but I am 100% certain that there are 12 ways to get AJo in the 1,326 hands, not 6.
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#14
08-02-2005, 11:54 PM
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Re: starting hands how many please respond
[ QUOTE ]
[ QUOTE ] Yes, but that counts A[img]/images/graemlins/spade.gif[/img] J[img]/images/graemlins/diamond.gif[/img] as a different hand from J[img]/images/graemlins/diamond.gif[/img] A[img]/images/graemlins/spade.gif[/img]. For example, suppose you want to figure out the probability of getting AJ offsuit. You could say there are four different Aces, and three offsuit Jacks per Ace, for 12 different hands. That's 12/2,652. Or you could divide both numbers by two, to get 6/1,326. You get the same probability either way. You just have to be consistent. [/ QUOTE ] I'm too tired to figure out where the error in this is, but I am 100% certain that there are 12 ways to get AJo in the 1,326 hands, not 6. [/ QUOTE ] ya know that might be why he said that
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#15
08-03-2005, 12:25 AM
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Re: starting hands how many please respond
[ QUOTE ]
[ QUOTE ] [ QUOTE ] Yes, but that counts A[img]/images/graemlins/spade.gif[/img] J[img]/images/graemlins/diamond.gif[/img] as a different hand from J[img]/images/graemlins/diamond.gif[/img] A[img]/images/graemlins/spade.gif[/img]. For example, suppose you want to figure out the probability of getting AJ offsuit. You could say there are four different Aces, and three offsuit Jacks per Ace, for 12 different hands. That's 12/2,652. Or you could divide both numbers by two, to get 6/1,326. You get the same probability either way. You just have to be consistent. [/ QUOTE ] I'm too tired to figure out where the error in this is, but I am 100% certain that there are 12 ways to get AJo in the 1,326 hands, not 6. [/ QUOTE ] ya know that might be why he said that [/ QUOTE ] Yeah but he's saying 12 of 2,652, it's actually 12 of 1,326. The problem is that the method he's using looks pretty good, I'm not really seeing where he missed it. The important thing to know is that 2,652 is how many ways you can receive your starting cards. That number is meaningless except that it is exactly double of the next number. 1,326 starting hand combinations.
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#16
08-03-2005, 12:27 AM
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Re: starting hands how many please respond
Oh I see why. Aaron, when you're doing the AJo calculation, you'd doing the math on how many aces times the offsuit jacks but you're not factoring in that you can receive them in either of two orders.
4 aces * 3 jacks * 2 ways to get it = 24 of 2,652 hands Thus, 12 of the 1,326 starting hands are AJo. Knew we both missed somethin.
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