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Tough question???
Okay I actually have two questions, one which is very easy.
The first question is: is the probability that someone will hit a pocket pair simply (4/52)*(2/2)=.0769? This should be basic intersection probability right? The next question I am very interested in and I am not sure if it is even possible to calculate but here it is anyways. suppose the flop has put a pair on the board: AA4, what is the probability that someone has one other A in their hand to make trips? is it: ((3/50)*(2/49)*(47/48))+((49/50)*(3/49)*(2/48)+((3/50)*(48/49)*(2/48))*(1/2) which if I calculated correctly would be .003673 any help with this would be great |
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