#1
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My Hand VS a Range of Hands
Hello All,
Situation: Player A is an ultratight player known to stay (not reraise) in a raised pot with AKx, AQx, AJx, QQ, JJ, 10 10. Let's assume since he didn't reraise he has no AA or KK. What are my odds with 2 2 against these range of hands and how do I represent this in a formula where x = my hand and a, b, c represent my opponents hands? Could it be as simple as taking my hand vs each possible opponent hand and getting the average? Thanks! |
#2
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Re: My Hand VS a Range of Hands
IRV,
You have to enumerate over all the possiblities and then take a weighted average. This is essentially impossible to do by hand. It's solved using a computer, but luckily the program is already written and you can download it for free. www.pokerstove.com Cheers, gm |
#3
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Re: My Hand VS a Range of Hands
When I run this range of hands in Poker Calculator (this is similar to Pokerstove), I get 42% equity for 22. In a 100,000 hand Monte Carlo simulation, it wins 42,051, draws 592, and loses 57,357.
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