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#1
12-18-2004, 03:57 AM
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Omaha Starting Hand Probability
What is the probability that AAxx (exactly two aces) will be dealt out to you as a starting hand?
I got close to 19:1. Here's my math: 52C4 = 270725 total starting hands 4C2 = 6 ways to get AA 6 * 48 (assuming AA dealt out to you already and no other A is wanted) * 47 = 13536 AAxx hands 13536/270725 = ~.05 = ~19:1 odds Did I do this right? 
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