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#1
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Re: Ultimate spreading Royal Holdem, but only limit
More interesting points:
If the board does not pair then the best you are doing is splitting unless you have the flush. This is for the simple reason that the best hand is on the table. If it is not a 3 or 4 flush board then it is a split. The question is: how many of the players will realise that? --------------------------------------------------- 2 pair is a dead hand. It cannot win ever. This is why: 1. If the board didn't pair then you are at best splitting 2. If the board did pair (not on your cards) then at least 1 of the other players (assuming all 6 are in) MUST have either a str or a FH. This is because only 3 cards don't play so one of the players MUST have the card that completes the str. ------------------------------------------------------- Trips are a dead hand unless you fill up. Same reason as above. ------------------------------------------------------- I'm sure there are more and I will add them if I think of them. This can be an amazing game to catch some fish. |
#2
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Re: Ultimate spreading Royal Holdem, but only limit
[ QUOTE ]
2 pair is a dead hand. It cannot win ever. [/ QUOTE ] I've seen several showdowns where two pair beat a worse two pair, or players split playing the 2 pair on the board. It happens more often shorthanded. |
#3
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Re: Ultimate spreading Royal Holdem, but only limit
Yep.
But if all 6 players are in to the showdown then this can NEVER happen. |
#4
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Chance of the board pairing
He we go.
Very simple calculation: Calculate the chance of board NOT pairing: First card is irrelevant. Say A. Second card must not be an A so can only be 16 out of the 19 left. Third card is 12/18. Fourth card is 8/17. Fifth is 4/16. Give 16/19 * 12/18 *8/17 * 4/16 = 0.066 So chance of pairing = 1-0.066 = 0.954 or 95.4%. Next I need to calculate what the chances are of winning if you have a PP. |
#5
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Re: Chance of the board pairing
[ QUOTE ]
He we go. Very simple calculation: Calculate the chance of board NOT pairing: First card is irrelevant. Say A. Second card must not be an A so can only be 16 out of the 19 left. Third card is 12/18. Fourth card is 8/17. Fifth is 4/16. Give 16/19 * 12/18 *8/17 * 4/16 = 0.066 So chance of pairing = 1-0.066 = 0.954 or 95.4%. Next I need to calculate what the chances are of winning if you have a PP. [/ QUOTE ] You can actually use standard tools like Pokenum or Pokerstove for this game, just mark all cards 9 and lower as dead. |
#6
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Re: Chance of the board pairing
[ QUOTE ]
[ QUOTE ] He we go. Very simple calculation: Calculate the chance of board NOT pairing: First card is irrelevant. Say A. Second card must not be an A so can only be 16 out of the 19 left. Third card is 12/18. Fourth card is 8/17. Fifth is 4/16. Give 16/19 * 12/18 *8/17 * 4/16 = 0.066 So chance of pairing = 1-0.066 = 0.954 or 95.4%. Next I need to calculate what the chances are of winning if you have a PP. [/ QUOTE ] You can actually use standard tools like Pokenum or Pokerstove for this game, just mark all cards 9 and lower as dead. [/ QUOTE ] [img]/images/graemlins/blush.gif[/img] Didn't think of that. Though it is a lot of typing. |
#7
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Re: Ultimate spreading Royal Holdem, but only limit
Here's my strategy so far:
Play AA. Catch top set. Cap every street. And I'll say it again, don't play in my games! |
#8
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Re: Ultimate spreading Royal Holdem, but only limit
[ QUOTE ]
Here's my strategy so far: Play AA. Catch top set. Cap every street. And I'll say it again, don't play in my games! [/ QUOTE ] That could actually work..i calculated that the chances of you getting AA is about 31:1. Stick in KK and AK and your rocking! Also, it seems your equity edge with big cards is reduced. I.e. AK is not as big a favorite against QJ as in normal Holdem. |
#9
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Re: Ultimate spreading Royal Holdem, but only limit
I rule at this game. |
#10
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Re: Ultimate spreading Royal Holdem, but only limit
I love that you are protecting the identity of your play money fish! [img]/images/graemlins/cool.gif[/img]
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