4 of a kind

[kingstalker]

Anybody know the odds of a player getting 4 of a kind two hands in a row in Texas hold them? Got busted out in a tournament today by a player who halved my stack when I had K-K vs Q-Q and we got it all in before the flop, and then got kncoked out on the very next hand when I had A-Q vs his 8-8 and he floped 4 of a kind again.

[anduril]

I'm not sure of the odds but I don't think that could possibly have sucked anymore than it did. I feel you man, right here

[kingstalker]

what really sucked about the first one was that the board came down 10-Q-8-Q and then to add insult to injury a king came down on the river giveing me a useless boat, on the very next hand when the same guy got 4 of a kind again I let out a weird maniac laughter when I saw him get the 4 again, time to go to the doctor for a check up!

[bigpooch]

Actually, the first number is exactly 2/245 so it is
15,005.25 to 1 against, not as rare as the other poster had
suggested (I think he had in mind a game other than holdem).

[hukilai]

The odds of having four of a kind is 0.00024. So, to have four of a kind in two hands in a row is about one chance from 16,000,000 (sixteen million) [img]/images/graemlins/smile.gif[/img]

[BruceZ]

The odds of having four of a kind is 0.00024. So, to have four of a kind in two hands in a row is about one chance from 16,000,000 (sixteen million)

The 0.00024 is off by a factor of 2, so the final answer is off by a factor of 4 (should be about 4 million).
(1/17)*C(48,3)/C(50,5) = 0.00048. This is the probability of getting dealt a pair and making quads. If you show your work, we can figure out where the factor of 2 went. Your answer would be correct for pat quads in 5 card draw. That is 13*48/C(52,5) = 0.00024.

For 7 card poker, this would be 13*C(48,3)/C(52,7) = 0.001681. This would include all quads, using both, one, or neither hole card. The chance of this twice in a row would be 1 in 354,025. The difference between this and the other answers is that it includes the cases where quads is on the board in addition to using 1 hole card or a pair in the hole, so it includes all quads. The case of quads on the board is not always a split pot as I refered to it earlier unless both players use the board for the kicker.

[bigpooch]

In holdem, if someone has a pocket pair, his chances of
making four of a kind (using his pocket pair) are

C(48,3)/C(50,5) = 17296/2118760 = 0.0081633

Squaring the above yields 0.0000066639. Of course, there
are less likely scenarios such as having quads on board or
making quads with just one card. For the case of making
quads with two different ranks in the holdem hand, the
number of combinations is:

2xC(47,2) = 2162

So for someone to have quads two hand in a row, the chances
(with this added possibility) are about 0.000084340. Of
course, your opponent did you in by the usual way!

[kingstalker]

Im not very good at math, is your number the same as the other guys 1 in 16 million? Basically I want to know so I can tell my friends about my bad beats and the odds of a certain occurance happening.

[bigpooch]

Sorry, my post did not go as I intended. It's actually
15005.25 to 1 against someone with a pocket pair to make
quads twice in a row.

[BruceZ]

It's actually 15005.25 to 1 against someone with a pocket pair to make quads twice in a row.

This assumes we already have the pairs twice in a row. The probability of being dealt a pair is 1/17, and it is (1/17)^2 to be dealt a pair twice in a row. So all together it is (1/17)^2*(1/15006.25) or 4,336,805 to 1.

If we consider the cases where we make quads with just 1 hole card, it becomes about 10 times more likely. See my other post in this thread.