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#1
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Calculating the Odds.
Is there a quick way to calculate odds to compare to pot odds based on number of outs I have?
At the moment, i'm doing 47/4 for four outs on the flop, but this can be tricky to work out quickly in my head. Do you just calculate odds for each number of outs then learn by rote? Or is there a quicker way to calculate on the spot? Thanks, G. |
#2
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Re: Calculating the Odds.
I'd just type up a chart and post it by your computer, after a few thousand hands you'll have it memorized to the point where you don't need it any more.
T |
#3
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Re: Calculating the Odds.
outs times 4 on the turn
outs times 2 on the river Quick and painless AND pretty accurate. |
#4
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Re: Calculating the Odds.
Thanks for the replies, i'll make up a list of outs and refer to that till i've got it.
I didn't really understand the x2 / x4 thing. How can you use that in a game? eg : pot is 8sb, bet is 1sb. pot odds are 8-1, 4 outs is 11.8-1. How can i use the x4 thing? if it's as % chance of getting a card, how can i compare this to the pot? bet / potsize? not sure i can do that in my head. [img]/images/graemlins/smile.gif[/img] |
#5
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Re: Calculating the Odds.
It's percentages.
I guess it's not easy to compare. You should memorize everything quickly enough anyway. |
#6
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Re: Calculating the Odds.
[ QUOTE ]
pot is 8sb, bet is 1sb. pot odds are 8-1, 4 outs is 11.8-1. How can i use the x4 thing? [/ QUOTE ] Picking a nit here, but it could be important in close situations. 47 cards unseen with 4 outs is actually 10.8:1 (rounded) not 11.8:1. You can either do 47/4 = 11.75 and then remember that one of those is yours, so 10.75:1. Or do 43/4 = 10.75:1. That's cards that don't help divided by cards that do. Regards, T |
#7
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Re: Calculating the Odds.
yes you're right (still new to 11-1 type odds).
I hadn't spotted that, thanks. It makes a lot of diffence to the calculation. |
#8
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Re: Calculating the Odds.
The last thing you want to do is calculate in your head at the table. Forget about the shortcuts and just memorize them. There really aren't that many numbers to memorize and you will know them off the top of your head in no time flat.
First: You don't need to know anything above 9 outs. If you have more than 9 outs to a lock, the pot will almost always offer you the proper odds. Second: Only memorize the odds for the next card to come. The odds for two cards to come are very misleading because you have to assume you'll be seeing BOTH the turn AND the river and the board can change dramatically when the turn is revealed. The difference between the odds for the next card on the flop and the next card on the turn are miniscule. Forget about the difference between the two and just memorize the odds for the next card to come on the turn. Pretty soon, you'll just know that a flush draw is 4.1 to 1. I googled "poker odds chart" and came up with this. Good luck! Onaflag.......... |
#9
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Re: Calculating the Odds.
Is it even possible to have 22 outs?
KQclubs 10J2 2 clubs could be 21 outs... I can't think of how you could get to 22 though. |
#10
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Re: Calculating the Odds.
[ QUOTE ]
Is it even possible to have 22 outs? KQclubs 10J2 2 clubs could be 21 outs... I can't think of how you could get to 22 though. [/ QUOTE ] I can only come up with 21 outs on the flop, using your example. You hold KJ clubs and your opponent holds 5h 5d. The flop comes Tc Jc 6h with two clubs. You can now hit 4 aces, 4 nines, 3 kings, 3 queens, and 7 clubs for 21 outs total. The most outs I can think of on the turn would be 25 and that comes from a situation where we take the same hand and board above and then drop a six on the turn. So now the setup is: You: Kc Qc Opponent: 5h 5d Board: Tc Jc 6h 6d You can now hit four aces (4) or (4) nines for your straight. You have 8 outs at this point. You can also hit three remaining tens (3) or jacks (3) for two overpair with top kicker. This gives you an additional six outs for 14 total. You then can also hit (3) remaining kings or queens (3) for top two pair, top kicker. This gives you another six outs, for 20 total. You can then hit any club that is a 2, 3, 4, 7, or 8 giving you 5 remaining outs for 25 total. You can only hit 5 as the Tc/Jc/Kc/Qc is gone, then we already have two clubs alloted to your nines and aces for outs, and either a 6c or 5c would give your opponent the winning full house. My numbers might be off slightly, correct me if so. |
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