#1
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Starting hand probabilities
In the probability tables in Brunson's Super System (page 572), it shows the probability of being dealt 2 aces is 0.45% with odds against as 220:1. 2 kings through 2 jacks 1.36% and 72.7:1 etc. (actually, I have another source somewhere that shows kings at 110:1 and Queens at 55:1 as I recall). My question is this: Why are the odds of getting two aces different from getting two kings (or any other pair) different?
The table does show, towards the bottom that any pair is 16:1 against- this makes sense since there are 4*4 possibilities, but what's with the 220:1? Thanks-- |
#2
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Re: Starting hand probabilities
Umm this is the way I think about getting dealt a pair of anything, and then more specifically one unique pair.
For any pair... First card is arbitrary. Second card needs to match first card. (3 remaining in a deck of 51) odds are 3/51 = 1/17 or 16:1 against to be dealt a matching card (any pair) Since there are 13 possible pairs, the odds of getting dealt a specific pair would be... (1/13)*(1/17) = 1/221 or 220:1 against. Therefore the chance of getting dealt ANY specific pair is 1 in 221. |
#3
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Re: Starting hand probabilities
I'm guessing you misread that and the real numbers are Kings or better, and then Queens or better...
Each individual pair is the same at 220:1. |
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