[Cyrus]

Thanks for the input, Bruce. I asked you for clarifications through a PM, but if you prefer to take it back here, it is quite alright.

The original question was "Can anyone tell me what the odds are of running into AA against your KK in a ten handed hold 'em game?" I took that to mean the poster wanted to find out abt the odds of running into any AA, which means one or two opponents having pocket Aces. You may have understood the question more clearly, though.

This is why I objected that the example with the "1,225 pieces of paper" on which each of the C(50,2) combinations is written, cannot aply in the "real world". The probability is indeed appoximated with [9*(6/1225)] but it is not exact. If we accept that more than 1 opponent can hold AA, this is no longer "considered a general model".

Thanks for clarifying.