View Single Post
  #6  
Old 09-16-2005, 07:46 AM
sthief09 sthief09 is offline
Senior Member
 
Join Date: Feb 2004
Location: duffman is thrusting in the direction of the problem (mets are 9-13, currently on a 1 game winning streak)
Posts: 1,245
Default Re: who wants to help me?

[ QUOTE ]

Note: f(x,y) must first be normalized by adjusting the constant if necessary such that the double integral of f(x,y) for x from 0 to 1, and y from 0 to 1, is equal to 1.


[/ QUOTE ]



[ QUOTE ]

a) double integrate f(x,y) for x from 0 to 1, and y from 1-x to 1.


[/ QUOTE ]

I got .02 from this. so far, so good I hope

[ QUOTE ]

b) integrate x*f(x,y) for x from 0 to 1.


c) integrate y*f(x,y) for y from 0 to 1.


[/ QUOTE ]


when I do this, I am getting 3y/10 and 6/15x^2, respectively. can this be right? can I get rid of the variables from there? the problem is it's a multivariate equation and I'm only integrating for one variable each, so I'm left with one, right?

[ QUOTE ]

d) double integrate xy*f(x,y) for x from 0 to 1, and y from 0 to 1.


[/ QUOTE ]

I'm getting 1/10 for this

[ QUOTE ]

e) cov(x,y) = E(xy) - E(x)*E(Y)

[/ QUOTE ]

since my answers for E(x) and E(y) have the other variable in them, I'm not going to get a number here. I'm assuming this can't be correct.

I'm going through my book now. you set me on the right path now. at least now I understand what I'm doing. before I was just mindlessly leafing through a book that I already read a couple of years ago
Reply With Quote