[jar]

[ QUOTE ]

BB*(1 - P(kill)) + 2*BB*P(kill)


[/ QUOTE ]
Wouldn't this be clearer written as
BB + BB*P(kill)?

If the rule is 2 hands in a row is a kill, P(kill) is 1/n in an n handed game, if you assume that all players are equally likely to win a hand. How close that is to true depends greatly on the players in a game. I'd guess the probability is higher than 1/n in a game with some loose players and some tight players. The loose players are much more likely to win consecutive hands, since they play more hands.