Re: AA chop, becoming a habit
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Just wondering what the odds are of another player being dealt the other 2 aces if you have 2
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(1225/N - 1) to 1, where N is the number of opponents.
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and what are the odds of it happening twice in a row?
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(1225/N)^2 - 1 to 1.
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I'm not very bright. What does N stand for here? There are 9 players in game if that matters.
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