Re: heads up % someone flops pr or better
Can you also show me the odds that both SB and BB would each flop a pair?
Assuming each of them does not already have a pair and also assuming that none of their cards overlap, ie, the two players hold a total of 4 distinct cards. First we calculate the ordered probability of the first card pairing player 1, the second card pairing player 2, and allowing the third card to be anything. Then we multiply that by 6 to account for all possible orderings.
(6/48)*(6/47)*6=.0954, about 10%
We can remove the above assumptions but it's a bit of a pain and I don't feel like doing it. Also, note that if you have a pair, this DOES NOT MEAN there is a 10% chance that your opponent also has a pair. That would be a differenct calculation entirely, and the answer would be closer to 30%.
gm
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