[squiffy]

If I recall correctly, Lee Jones states that you can expect to be dealt AA once every 200 hands or so. But he does not show how to calculate this.

You would need to know how many different AA combinations are possible and which ones to throw out.

And you would need to divide by the total number of two card hand combinations that are possible.

1 in 200 deals seems a bit low to me. But there are 4 aces out of the 52 card deck, so about 7.6% of the cards are Aces.

So then you need to figure out how many hands are dealt on average per hour. I have heard some say 100 hands an hour. But that sounds much too high to me, even for online play.

Then you can calculate how many hours you would have to play, on average, to get one AA hand.

If there are four aces AcAdAhAs.

I guess there are 6 unique two card combinations of AA?

AcAd AhAd AsAs
AcAh AhAs
AcAs

I used to remember a simple formula for this. Maybe it is n-1 + n-2 + n-3 . . . . where n is the number of cards, here 4 cases. So 3 + 2 + 1 = 6.