Re: Dead cards and counting outs.
Not really. I know it is correct, and I completely understand your example, but I've still got that itch. I'll try some math. Here goes.
My 9 opponents have collectively C(47,18) sets of possible cards in their hands. I want to see what percentage of the time I'm drawing to all my outs. To do that, I'm going to define the set of hands my opponents could collectively have that don't have my outs in them, or C(47,39)
C(47, 18) = 4,568,648,125,690
C(47, 39) = 314,457,495
I get an exponential number when I do this percentage, so subtract this from the total possible sets, and get the percentage that I'm NOT drawing to all my outs:
99.993117%
I'm not sure if my math is correct, as I'm just getting into combinatorics. Someone bash me on the head if I butchered this too much.
All this being said, I know (though not intuitively) that it doesn't matter. I just don't get it.
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