Well I hate to disappoint, but I cannot find my answers
Here is what I tried for on the turn:
Following your logic, my first Combo was still C(2,1) since there are 2 ways to pick one ace. From there im a bit fuzzy since in your example you multiplied that value times the combo of ways to not flop an A, and then divided by number of ways to choose one card out of the remaining 47. So. . .
C(2,1)*C(45,0)/C(47,1)=0.042553 where
C(2,1)=Number of ways to choose one A of the two remaining
C(45,0)=Not sure
C(47,1)=Number of ways to choose one turn card
I noticed that the sum of the numerator values equal the combo values on the bottom, so I followed that logic for part of that, although now I cant really interpret my answer since I dont know what the odds really are of making it on turn. Please correct me, and thanks