Thread: How to count the combinations to get a pair in the hole.
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Old 09-02-2004, 11:48 AM
Precision1C Precision1C is offline
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Default Re: How to count the combinations to get a pair in the hole.
If one A is out the number of combinations of AA is C(3,2)=3!/(2!1!)=3. C(n,k)=number of combinations of k items from set of size n= n!/(k!*(n-k)!)
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