Re: How to count the combinations to get a pair in the hole.
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I know that there are six combinations of AA and I know that there are 16 combinations of AK. To figure that out I just take 4*4=16. If one king is gone I just take 4*3=12 and find out that there is 12 combinations left.
But I just cant figure out how to count the combinations of for an example AA. Plz help me with this. I am going craaaazy!
Thx
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C(4,2) = 4*3/2 = 6. The divide by 2 is so we don't count each combination twice.
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