[SwissPoker]

1. I was wondering how Mike Caro arrives at 2592 combinations to Aces-up in 5draw (no joker) when drawing 3 to 2 aces?

I tried to figure it like this:

pair combinations (3 ranks with 3 cards): 3 * C(3,2) * 45 = 3 * 3 * 45 = 405
pair combinations (9 ranks with 4 cards): 9 * C(4,2)* 45 = 9 * 6 * 45 = 2430

for a total of 2835 two pair combinations

What am I doing wrong?


2. I tried to figure how Mike Caro arrives at 1854 combinations to 3-Aces in 5draw (no joker) when drawing 3 to 2 aces?

I tried to figure it like this:

no pair combinations (3 ranks with 3 cards): 3 * C(3,2) = 3 * 3 = 9
no pair combinations (9 ranks with 4 cards): 4 * C(9,2) = 4 * 36 = 144

What am I doing wrong? And how do I arrive at the exact combinations?

Thanks for any help.