Re: Quick question: at least one player dealt pocket pair
[ QUOTE ]
This gets into conditional probability if you're a player at the table, because someone else is MORE likely to be dealt a pair if you are, and they are less likely to be dealt one if you aren't.
[/ QUOTE ]
The conditional part just manifests itself in a simple change to the numbers used in the inclusion-exclusion calculation I linked to.
[ QUOTE ]
Anyways, assuming you're a spectator.
Chance of at least no PP being dealt 1-(16/17)^n. where n=number of players at the table.
[/ QUOTE ]
That's an approximation since it assumes that the players' hands are independent, though it is a very good approximation in this case. This is discussed in the first inclusion-exclusion thread I linked to. Use the inclusion-exclusion method to get the exact answer (to any desired accuracy).
|