Re: Probability Question (non-poker related)
If every game is a coinflip...
The odds of picking one game is 1/2. The odds of picking two are (1/2)*(1/2).
Therefore, the odds of picking sixty three games is 1/2 taken to the sixty-third power, or one in 9,223,372,036,854,780,000.
I can't count that high.
Of course, they aren't coinflips.
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