Re: Odds the board pairs?
Asuming you don't look at your hole cards the odds of the board exactly pairing once are 13*C(4,2)*48*44*40/6 divided by C(52,5)=42.3% The odds of no matching cards appearing in dummy are (52*48*44*40*36/5!)/C(52,5)=50.7%.
C(X,Y)=X!/(Y!*(X-Y)!) which represents the number of unique combinations of Y items from a pool of size X.
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