Re: AA vs. AA 2 out of 3 hands?
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Odds of A-A vs. A-A on a given hand, full ring...I believe:
C(10,2) * 1/C(52,4) = 45/270725 = .0166% or about 6015 to 1.
For this to happen exactly 2 times in 3 hands:
=BINOMDIST(2,3,45/270725,FALSE) = .00000828738% = ~12,066,538.7-to-1
Someone correct me if I'm wrong.
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the math looks right to me.
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