Re: AA vs. AA 2 out of 3 hands?
Ok. So if you change it to C(52,4) or 4/52 * 3/51 * 2/50 * 1/49 for the specific case of AA vs. AA, I believe the math presented should hold up. Really not likely. Granted, this is only the odds that you sit down at a table and this happens on the first three hands. If you played 20,000,000 hands, this situation would be much more likely to occur at some point.
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