Re: 3 card poker problems....
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Ok so how in 3 card poker would you calculate the probability of recieving 3 of a kind? I figured it would be (C(4,3)*13)/C(52,3). This gives me a really small number though and unsure if it is correct.
And I am really unsure of how to compute the probability of getting a straight. I was thinking (12*4^3-48)/C(52,3). Does this seem right or not? Thanks in advance.
SGS
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3 of kind looks right.
Straight looks right except for the " - 48" part. Where are you getting that?
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