Re: figuring pot odds quickly
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there is 90 in the pot,
the other guy bets 10 and now it is 10:1 odd for my call.
the Board is Jh, 3c, 7h and I hold A,Th
If I put the other guy on the J, I know I have 9 clean outs and a possibe 12 outs: the 9 hearts and the 3 aces so at the table I need to devide the 12 by the 21 cards left (assuming a full table and a burn card). If I have done the math write I have a 57% chance of hitting a card that helps me amd I am only calling 10%.
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if you have 12 outs after the flop you divide the 12 (outs) by 47 (unknown cards, not the 21 that are left to be dealt), so you have a 25% chance of hitting on the turn
however, i think it's easier and quicker to divide the 47 (unknown cards) by the 12 (outs) = 3.9, and take away 1 = 2.9, which gives you the odds of hitting on the turn, 2.9 to 1, which you then compare with the pot odds of 10 to 1 (in this case)
another example: if you have an open-ended straight after the flop you divide 47 by 8 = 5.9, take away 1 = 4.9, which gives you 4.9 to 1 odds of hitting on the turn
if you miss, you divide 46 by 8 = 5.75, take away 1 = 4.75, which gives you 4.75 to 1 odds of hitting on the river
of course, in reality, and for ease, you would normally be ok with saying 47 divided by 8 is 6 minus 1 is 5 to 1 odds of hitting
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